Question

Find the area of rhombus one of whose diagonals measures 8 cm and the other 10 cm

Answer 1

1/2 × 8 × 10 = 40 cm^2

Answer 2

Answer:

$40cm^2$

Step-by-step explanation:

Given :Diagonals of rhombus measures 8 cm and the other 10 cm

To find : Area of rhombus

Solution:

Length of one diagonal i.e. p = 8 cm

Length of other diagonal i.e. q = 10 cm

Area of rhombus = $\frac{1}{2} \times p \times q$

Substitute the values :

Area of rhombus = $\frac{1}{2} \times 8 \times 10$

Area of rhombus = $40cm^2$

Hence The area of the given rhombus is $40cm^2$