Question

Find the area of Rhombus one of whose diagonals measures 8 cm and the other 10 cm.
(a) 47 cm²
(b) 34 cm²
(c) 40 cm²
(d) 64 cm²

Answer 1

area of a rhombus=1/2 ×d1×d2
=1/2×8×10
4×10
40cm^2

Answer 2

Solution:

We know that area of Rhombus is given by

$\frac{1}{2} \times d1 \times d2$
here d1 and d2 are the diagonal of rhombus.

Given that
$d1 = 8 \: cm \\ \\ d2 = 10 \: \: cm$
Area
$= \frac{1}{2} \times 10 \times 8 \\ \\ = 5 \times 8 \\ \\ = 40 \: {cm}^{2}$
Hence option (C) is correct.

Hope it helps you.