Math, asked by monika2347, 10 months ago

find the area of Rhombus the length of whose diagonals are 30 and 16 also find the perimeter of rhombus​

Answers

Answered by KokilaAbhishek
0

Step-by-step explanation:

Perimeter of rhombus = 4a

a = √d1^2 + d2^2 /2

P = 2√d1^2 + d2^2

= 2√30^2 + 16^2

= 2√900 + 256

= 2√1156

= 2*34 = 68

Now , we find area of rhombus

A = d1 * d2/2 = 30*16/2 = 240

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