find the area of rhombus the lengths of whose diagnols are 12cm and 10cm
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AnSwEr -:
•Area of Rhombus = 60 cm^2
_______________________________
_______________________________
•Formula to find area of diagonal-:
“1/2 x d1 x d2”
D1 = Diagonal 1
D2 = Diagonal 2
_______________________________
•Given,
D1 = 12 cm
D2 = 10 cm
•To find
•Area of Rhombus-:
1/2 x d1 x d2
1/2 x 12 x 10
1/2 x 120
60 cm^2
_______________________________
•Area of Rhombus = 60 cm^2
_______________________________
•Rhombus -:
A Rhombus is a quadrilateral whose four
sides all have the same length.
_______________________________
•Formula to find area of Rhombus and
trapezium -:
•Rhombus-: “1/2 x d1 x d2”D1 = Diagonal 1
D2 = Diagonal 2
•Trapezium-: “1/2 x h x (a+ b)”h= height
(a+b) = sum of parallel sides.
______________________________
•Area of Rhombus = 60 cm^2
_______________________________
_______________________________
•Formula to find area of diagonal-:
“1/2 x d1 x d2”
D1 = Diagonal 1
D2 = Diagonal 2
_______________________________
•Given,
D1 = 12 cm
D2 = 10 cm
•To find
•Area of Rhombus-:
1/2 x d1 x d2
1/2 x 12 x 10
1/2 x 120
60 cm^2
_______________________________
•Area of Rhombus = 60 cm^2
_______________________________
•Rhombus -:
A Rhombus is a quadrilateral whose four
sides all have the same length.
_______________________________
•Formula to find area of Rhombus and
trapezium -:
•Rhombus-: “1/2 x d1 x d2”D1 = Diagonal 1
D2 = Diagonal 2
•Trapezium-: “1/2 x h x (a+ b)”h= height
(a+b) = sum of parallel sides.
______________________________
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