Find the area of rhombus where each side measures 20cm and one of its diagonal is 32 cm.
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0
Answer:
384 cm square
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Answered by
3
Answer:
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Find Area of Rhombus
Side = 20 cm
one diagonal is 24 cm
→□ABCD BC = 24 cm, so, BM=MC=
2
24
=12cm
→ diagonals AD=AM+MD
→In△AMC, using Pythagoras theorem
AC
2
=AM
2
+MC
2
(20)
2
=AM
2
+(12)
2
AM
2
=(20)
2
+(12)
2
=400−144
AM
2
=256
AM=
256
AM=16cm
→AM=MD=16cm
→ Area of Rhombus =
2
1
× Product of diagonal
=
2
1
×(AD.BC)
=
2
1
×((16+16).24)
=
2
1
×32×24
=384cm
2
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