Question

• Find the area
of rhombus which
side measures 5 cm and one diagonal
8 cm​

Answer 1

Answer:

48cm²

Step-by-step explanation:

d1= 8cm ,side =5

by pythagoras theorem d2 is equal to 6cm

area = d1 × d2

= 8×6

= 48

Answer 2

Diagonals bisect each other and they are perpendicular in rhombus

=> Let half the length of second diagonal be x

=> As two diagonals and a side form right angled triangle ;

⇒x2+42=52

⇒x=3

⇒length of 2nd side =2x=6cm

=> Area of rhombus =21d1d2

                             =21×8×6

                              =24cm²

I hope this will help you dear..

Always stay safe and stay healthy..