Question

Find The Area Of Rhombus Whose 1 diagonal is 8cm Long and Other diagonal is 4 cm .
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Answer 1

Answer:

16 cm^2

Step-by-step explanation:

formula

(1/2) x (diagonal 1) x ( diagonal 2)

=(1/2)*8*4

Answer 2

AnswEr -:

• $\underline {\mathrm {\star{\pink{The\:Area \:of\:Rhombus \;is\:16\:cm^{2}\:.}}}}$

Explanation-:

$\mathrm {\bf{ Given \:-:}}$

• Diagonal 1 or One Diagonal of Rhombus is 8 cm .

• Diagonal 2 or Other Diagonal of Rhombus is 4 cm

$\mathrm {\bf{ To\:Find \:-:}}$

• Area of Rhombus.

$\mathrm {\bf{\dag{ Solution \:of\:Question \:-:}}}\:$

$\underbrace {\mathrm {\bf{ Understanding \:the\:Concept \:-:}}}$

• We have to find Area of Rhombus when Diagonal 2 and Diagonal 1 of Rhombus is given .

• Firstly Put the known Values [Diagonal 2 and Diagonal 1 of Rhombus ] in the Formula for Area of Rhombus.

• By Putting this we can get the Area of Rhombus.

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$\underline {\mathrm {\bf{\dag{ Finding \: Area \:of\:Rhombus \:-:}}}}\:$

As , We know that,

• $\underline{\boxed{\star{\sf{\red{ Area_{(Rhombus)}  \: = \dfrac{1}{2} \times Diagonal _{1} \times Diagonal _{2} \: sq.units }}}}}$

$\mathrm{\bf{\blue {Here \:\: -:}}} \begin{cases} \sf{\blue{The\:Diagonal _{1} \:or\:one\:Diagonal \:of \:the\:Rhombus \: \:is\:= \frak{8\:cm}}} & \\\\\sf{\pink{The\:Diagonal _{2} \:or\:other\:Diagonal \:of \:the\:Rhombus \: \:is\:= \frak{\:4\:cm}}} \end{cases}$

Now By Putting known Values in Formula for Area of Rhombus-:

• $\qquad \quad \qquad \quad \longmapsto {\mathrm { Area \:= \dfrac{1}{2} \times 8 \times 4 }}$

• $\qquad \quad \qquad \quad \longmapsto {\mathrm { Area = \dfrac{1}{\cancel {2}} \times \cancel {8} \times 4 }}$

• $\qquad \quad \qquad \quad \longmapsto {\mathrm { Area\:= 4 \times 4 }}$

• $\qquad \quad \qquad \quad \underline {\boxed{\pink{\mathrm { Area = 16\:cm^{2} }}}}$

Hence ,

• $\underline {\mathrm {\star{\pink{The\:Area \:of\:Rhombus \;is\:16\:cm^{2}\:.}}}}$

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$\large { \boxed {\mathrm |\:\:{\underline {More \:To\:Know\:-:}}\:\:|}}$

• Area of Rectangle = Length × Breadth sq.units

• Area of Square = Side × Side sq.units

• Area of Triangle = ½ × Base × Height sq.units

• Area of Trapezium = ½ × Height × ( a +b ) or Sum of Parallel sides sq.units

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