Question

Find the area of rhombus whose diagonal 13m and the other is twice the first one

Answer 1

Answer:

169 m^2

Step-by-step explanation:

Diagonal 1 of rhombus=13 m

Diagonal 2 of rhombus= 2×13 =26 m

Area of rhombus=1/2×d1×d2=1/2×13×26=169 m^2

Answer 2

SOLUTION:-

Given,

Rhombus of the diagonals;

1st diagonal= 13m

2nd diagonal, 2x of first diagonal= 2× 13

=) 26m

Now,

Area of rhombus:

$= > \frac{1}{2} \times d1 \times d2 \\ \\ = > \frac{1}{2} \times 13 \times26 \\ \\ = > 13m \times 13m \\ \\ = > 169 {m}^{2}$

hope it helps ☺️