Question

Find the area of rhombus whose diagonals are 13 cm, 10 cm​

Answer 1

Answer:

From the question,

Rhombus ABCD with centre O,

side (S) = 13 cm

shorter diagnol (P) = 10 cm

consider triangle OCB,

applying Pythagoras theorem,

OC = √ (BC^2 - OB^2 ) = √(169 - 25) = √ 144 = 12

OC = 12 cm

longer diagnol (AC) = AO + OC = 2OC = 2 x 12 = 24

Longer diagnol, AC = 24 cm.

Area of rhombus ABCD = [(AC x BD) / 2 ] = 10 x 24 / 2

Area of Rhombus ABCD = 120 sq.cm

Answer 2

Answer:

I think this is your required answer

Step-by-step explanation:

Diagonas of rhombus are 13,10 cm

d1=13 cm

d2=10 cm

Area of rhombus=1/2.d1.d2

=1/2.13.10

=5.13

=65