Question

Find the area of rhombus whose diagonals are AC=4cm and BD=6cm.
answer fast as fast as u can. class 8.​

Answer 1

Answer:

Here is your solution

GIVEN :-

abcd IS A RHOMBUS

so,

ab=bc=cd=ad

ac = 8 cm

bd = 6 cm

Now,

we know that In rhombus diagonal bisect each other at center and 90° formation also.

oa = oc = 4cm

ob = od = 3cm

Now,

In right △ boc

\begin{gathered}ob{}^{2} + oc {}^{2} = bc {}^{2} \\ \\( 3cm) {}^{2} + (4cm) {}^{2} = bc{}^{2} \\ \\ 9cm {}^{2} + 16cm {}^{2} = bc {}^{2} \\ \\ 25cm {}^{2} = bc {}^{2} \\ \\ \sqrt{25cm {}^{2} } = bc \\ \\ 5cm = bc\end{gathered}

ob

2

+oc

2

=bc

2

(3cm)

2

+(4cm)

2

=bc

2

9cm

2

+16cm

2

=bc

2

25cm

2

=bc

2

25cm

2

=bc

5cm=bc

Note:-

all sides of rhombus is equal .

so all sides of rhombus is 5 cm