Math, asked by manjuchoudhary57, 4 months ago

Find the area of rhombus whose diagonals are of length 20 cm and 15 cm.

Answers

Answered by simran7539
11

Solution

Given :-

  • Diagonals of the rhombus are 20 cm and 15 cm.

To Find :-

  • The area of the rhombus.

Step-by-Step-Explaination :-

As we know that :-

Area of the rhombus = 1/2 × D1 × D2

Where,

  • D1 = 20 cm

  • D2 = 15 cm

Putting the respective value,

Area of the rhombus = 1/2 × 20 × 15

Area of the rhombus = 300/2

Area of the rhombus = 150

Hence,

Area of the rhombus = 150 cm

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Know More :-

Perimeter of Rectangle = 2( L + B )

Perimeter of square = 4 × Side

Perimeter of triangle = AB + BC + CA

Area of Rectangle = L × B

Area of Square = ( side ) ²

Area of Rhombus = Product of Diagonal/2.

Area of Parallelogram = Base × Height.

Area of triangle = 1/2 × base × height .

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Answered by thebrainlykapil
140

Given :-

  • Length of First Diagonal = 20cm
  • Length of Second Diagonal = 15cm

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To Find :-

  • The Area of the Rhombus .

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Solution :-

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⇒ Area = ½ × product of its diagonals

⇒ Area = ½ × ( 20 × 15 )

⇒ Area = ½ × 300

⇒ Area = 150cm²

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Therefore, The Area of Rhombus is 150cm²

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Additional Info :

Formulas Related to Area :-

  • Area of Square = Side x Side
  • Area of Rectangle = Length × Breadth
  • Area of Triangle = ½ × base x height
  • Area of parallelogram = base x height
  • Area of circle = πr²
  • Area of Rhombus = ½ × product of its diagonals
  • Area of Trapezium = ½ × height × sum of parallel sides
  • Area of Polygon = sum of the area of all regions into which it is divided

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