Question

find the
area of rhombus whose
diagonals area of length 10 cm and 8.2 cm​

Answer 1

Given: Diagonals of the rhombus are of length 10cm and 8.2cm.

Need to find: Area of the rhombus.

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$\underline{\bf{\dag}\frak{\;As\;we\;know\;that\;:}}$

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$\star\;\boxed{\pink{\sf{Area\;_{(rhombus)}=\dfrac{1}{2}\times d_1\times d_2}}}$

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Therefore,

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$:\implies\sf{Area=\dfrac{1}{2}\times 10\times 8.2}\\\\\\\\:\implies\sf{Area=\dfrac{1}{2}\times 82}\\\\\\\\:\implies\underline{\boxed{\purple{\frak{Area=41\;cm^2}}}}{\;\bigstar}$

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$\therefore\;{\underline{\sf{Hence,\;the\;area\;of\;the\;rhombus\;is\;{\frak{41\;cm^2}}}.}}$

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Answer 2

The area of the rhombus is

1/2×8.2×10=41 m^2

.