Question

find the area of rhombus whose diognals areas of length 6cm and 3cm​

Answer 1

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Answer 2

$\begin{gathered}\begin{gathered}\bf \: Given - \begin{cases} &\sf{Diagonal \: of \: rhombus,d_1 = 6 \: cm} \\ &\sf{Diagonal \: of \: rhombus,d_2 = 3 \: cm} \end{cases}\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\bf \:To\: find\:- \begin{cases} &\sf{Area_{(rhombus)}}  \end{cases}\end{gathered}\end{gathered}$

$\begin{gathered}\Large{\sf{{\underline{Formula \: Used - }}}}  \end{gathered}$

$\boxed{ \bf{ \: Area_{(rhombus)} = \dfrac{1}{2} \times d_1 \times d_2}}$

where,

$\: \: \: \: \: \: \bull \: \sf \: d_1 = Diagonal \: of \: rhombus$

$\: \: \: \: \: \: \bull \: \sf \: d_2 = Diagonal \: of \: rhombus$

$\large\underline{\sf{Solution-}}$

Given that

$\: \: \: \: \: \: \bull \: \sf \: d_1 = Diagonal \: of \: rhombus = 6 \: cm$

$\: \: \: \: \: \: \bull \: \sf \: d_2 = Diagonal \: of \: rhombus = 3 \: cm$

Therefore,

• Area of rhombus is

$\rm :\longmapsto\:Area_{(rhombus)} = \dfrac{1}{2} \times d_1 \times d_2$

$\rm :\longmapsto\:Area_{(rhombus)} = \dfrac{1}{2} \times 6 \times 3$

$\rm :\longmapsto\:Area_{(rhombus)} = 9 \: {cm}^{2}$

Additional Information :-

Rhombus :-

• A rhombus is a special case of a parallelogram, and it is a four-sided quadrilateral.

In a rhombus,

• Opposite sides are parallel.

• The opposite angles are equal.

• All the sides of a rhombus are equal in length.

• The diagonals bisect each other at right angles.

• The rhombus is also called a diamond or rhombus diamond.

$\boxed{ \bf{ \: Area_{(rhombus)} = base \times height}}$

$\boxed{ \bf{ \: Perimeter_{(rhombus)} = 4 \times side}}$