Question

Find the area of Rhombus whose one side is 13 cm and one diagonal is 26 cm.

Answer 1

Answer:

120 cm²

Step-by-step explanation:

The diagonal will be found by Pythagoras theorem :

Let the other diagonal half be d .

Question is wrong it will be 24 cm .

So :

d² = 13² - 12²

⇒ d² = 169 - 144

⇒ d² = 25

⇒ d = 5

Diagonal = 10 cm

Area = 1/2 × 10 × 24

⇒ 12 × 10

⇒ 120 cm²

Answer 2

hi

there is some mistake in your question.

The length if diagonal need to be 24cm.

here is your answer

Area of rhombus = 1/2× product of diagonals.

now, As diagonal of rhombus bisect each other.

Hence,by Pythagoras theorem,

12^2+ oc^2= 13^2

= 144+ OC^2 = 169

=OC= 5 cm

and AC = 5×2=10cm

Now area = 1/2× 10 × 24

= 120cm^2

hope it helps

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