Find the area of Rhombus whose one side is 13 cm and one diagonal is 26 cm.
Answers
Answered by
2
Answer:
120 cm²
Step-by-step explanation:
The diagonal will be found by Pythagoras theorem :
Let the other diagonal half be d .
Question is wrong it will be 24 cm .
Half of 24 cm = 12 cm
So :
d² = 13² - 12²
⇒ d² = 169 - 144
⇒ d² = 25
⇒ d = 5
Diagonal = 10 cm
Area = 1/2 × 10 × 24
⇒ 12 × 10
⇒ 120 cm²
Answered by
0
A=pq/2
a=√p^2+q^2/2
Solving forA
A=1/2p√4a^2﹣p^2
= 1/2*24*√4*13^2﹣24^2
=120cm²
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