Math, asked by hzgjj, 1 year ago

Find the area of Rhombus whose one side is 13 cm and one diagonal is 26 cm.

Answers

Answered by Anonymous
2

Answer:

120 cm²

Step-by-step explanation:

The diagonal will be found by Pythagoras theorem :

Let the other diagonal half be d .

Question is wrong it will be 24 cm .

Half of 24 cm = 12 cm

So :

d² = 13² - 12²

⇒ d² = 169 - 144

⇒ d² = 25

⇒ d = 5

Diagonal = 10 cm

Area = 1/2 × 10 × 24

⇒ 12 × 10

⇒ 120 cm²

Answered by Anonymous
0

A=pq/2

a=√p^2+q^2/2

Solving forA

A=1/2p√4a^2﹣p^2

= 1/2*24*√4*13^2﹣24^2  

=120cm²

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