Question

Find the area of rhombus whose one Side is 15 cm and one diagonal is 24 cm.

Answer 1

Answer: The answer should be 216 cm2

Step-by-step explanation:Let AC and BD be the two diagonals intersect at O

Let AC =24 Therefore AO=12

AOB is a right angled triangle

BO=152−122−−−−−−−−√=9

BD=18 cm

Area = 1/2*AC*BD

=1/2*24*18=216 cm^2

hope this helps u

Answer 2

Answer:

216 cm^2

Step-by-step explanation:

As we know that the diagonals of a rhombus bisect each other perpendicularly.

Thus, by Pythagorean theorem,

$(\frac{1}{2}*24 )^{2}  +( \frac{Diagonal}{2}) = 15^2$

$12^2 + \frac{Diagonal^2}{4} =225$

Diagonal = $\sqrt{(225-144) * 4}$

Diagonal = 9 * 2

Thus,

The required diagonal is 18 cm

Area of Rhombus = Product of diagonals/2

= 18*24/2

=432/2 cm^2

=216 cm^2