Question

Find the area of rhombus whose one side is equal to 10 cm and the length of one of the diagonals is 12 cm

Answer 1

may be this is helpful for u

Answer 2

Answer:

96 CM SQ

Step-by-step explanation:

Let the diagnals be d1, d2.

Given: d1 = 12cm

Since diagonals bisect each other at right angles,

By Pythagoras theorem,

( d1 / 2 ) ^2 + ( d2 / 2 ) ^2 = 10 ^2

( 12 / 2 ) ^2 + ( d2 / 2 ) ^2 = 100

36 + ( d2 / 2 ) ^2 = 100

( d2 / 2 ) ^2 = 64

d2 / 2 = 8

d2 = 16 cm

Area of a rhombus =

( 1 / 2 ) × product of diagonals

= ( 1 / 2 ) × d1 × d2

= ( 1 / 2 ) × 12 × 16

= 96 cm ^2