Question

Find the area of rhombus whose perimeter and one of its diagonals are 68 cm and 30 cm respectively.​

Answer 1

Answer:

240cm2

Step-by-step explanation:

perimeter of rhombus = 68cm

so length of one of its sides is

4a=68cm

a=17 cm

the rhombus can be divided into 2 isosceles triangles with equal sides length 17cm and unequal sides length 30cm.

area of the rhombus= 2× area of the isosceles triangle

area of isosceles triangle=√ s(s-a) (s-b) (s-c)

where s is the semi perimeter and a, b, c are sides of the triangle

s= 17+17+30/2

s=32cm

area of triangle= √32 (32-17) (32-17) (32-30)

√32×15×15×2

√14400

120cm2

area of triangle is 120 cm2

area of rhombus= 2×120

240cm2

Answer 2

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