Question

find the area of rhombus whose perimeter is 200m and one of the diagonals is 80m

Answer 1

Perimeter of rhombus=4(side)
                             200=4(side)
                               50 m=side
∵Diagonals of rhombus bisect each other at right angles,
∴Diagonal=40 m
Let other diagonal=x
x²+(40)²=(50)²                                      (By pythagoras Th.)
x=30
Now, ar. of rhombus=d₁d₂/2
                                ⇒40*30/2=60 m²

Answer 2

your answer is in the attachment...

hope it helps...