find the area of rhombus whose perimeter is 200m and one of the diagonal is 80m
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1
a= p*q/2
so its gonna be 200*80/2
which is 16000/2=8000
so its gonna be 200*80/2
which is 16000/2=8000
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side of rhombus = perimeter/4 = 200/4 = 50 m
using pythagoras theoram ,
(50)^2 = (40)^2 + (x)^2
2500 = 1600 +(x)^2
x= 30
length of other diagonal = 2x30 =60m
area of rhombus = 1/2x60x80 = 2400m^2
using pythagoras theoram ,
(50)^2 = (40)^2 + (x)^2
2500 = 1600 +(x)^2
x= 30
length of other diagonal = 2x30 =60m
area of rhombus = 1/2x60x80 = 2400m^2
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