Math, asked by devansh42, 1 year ago

Find the area of rhombus whose perimeter is 200m. one of diagonal is 80m.

Answers

Answered by h15
0
Perimeter of rhombus = 200m
Side of rhombus = 200/4==50

As we know diagonals of rhombus bisect each other
So , Diagonal/2 == 80/2=40

So by pythagoras theorem
Another diagonal == 30m

As diagonal/2==30/2==15m

Area of rhombus == 1/2×d1 × d2
= 1/2 × 15 × 40
= 20×15=300m^2

HOPE THIS HELPS YOU! !
Answered by NavyaThakral
0

answer is in the attachment...

hope it helps...

Attachments:
Similar questions