Find the area of rhombus whose perimeter is 200m. one of diagonal is 80m.
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Perimeter of rhombus = 200m
Side of rhombus = 200/4==50
As we know diagonals of rhombus bisect each other
So , Diagonal/2 == 80/2=40
So by pythagoras theorem
Another diagonal == 30m
As diagonal/2==30/2==15m
Area of rhombus == 1/2×d1 × d2
= 1/2 × 15 × 40
= 20×15=300m^2
HOPE THIS HELPS YOU! !
Side of rhombus = 200/4==50
As we know diagonals of rhombus bisect each other
So , Diagonal/2 == 80/2=40
So by pythagoras theorem
Another diagonal == 30m
As diagonal/2==30/2==15m
Area of rhombus == 1/2×d1 × d2
= 1/2 × 15 × 40
= 20×15=300m^2
HOPE THIS HELPS YOU! !
Answered by
0
answer is in the attachment...
hope it helps...
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