find the area of rhombus whose perimeter is 80cm and one of whose diagonals is 24cm.
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Rhombus
Solve for
area
A
=
384
cm²
p
Diagonal
cm
P
Perimeter
cm
Using the formulas
A
=
p
q
2
P
=
4
a
a
=
p
2
+
q
2
2
Solving for
A
A
=
1
4
p
P
2
﹣
4
p
2
=
1
4
·
24
·
80
2
﹣
4
·
24
2
=
384
cm²
Solve for
area
A
=
384
cm²
p
Diagonal
cm
P
Perimeter
cm
Using the formulas
A
=
p
q
2
P
=
4
a
a
=
p
2
+
q
2
2
Solving for
A
A
=
1
4
p
P
2
﹣
4
p
2
=
1
4
·
24
·
80
2
﹣
4
·
24
2
=
384
cm²
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