Question

find the area of rhombus whose perimeter is 80m and one of whose diagonal is 24m​

Answer 1

side of rhombus= 20

second diagonal of rhombus=32

so area of rhombus=568

Answer 2

Answer:

We know that area of rhombus

A=d1*d2 then,

Perimeter of rhombus =4a

a=√d1^2 + d2^2

A= 1/4*p√p^2 - 4q^2

= 1/4*24√80^2 - 4*24^2

= 6√6400 - 2304

= 6√4096 = 6*64 = 384m^2