find the area of rhombus whose perimeter is 80mt and one diagonal is 24mt.
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In a rhombus, all sides are equal .
Perimeter = 4 * side
Side = 80/4 = 20 m.
Given one diafgonal, d = 24 m.
A rhombus has four triangles and four of them are right angled triangle.
Length of one side = Diagonal/2 = 12m
Length of other side = 2ndDiagonal/2
Length of hypotenuse = 20m .
Now, According to Pythagoras theorem.
20² - 12² = ( Diagonal /2 )²
400 - 144 = (Diagonal /2 )²
√ 256 = Diagonal / 2
16 = Diagonal /2
Diagonal = 32 m .
We have Diagonals 32 m, 24 m.
Area = 1/2 * 32 * 24 = 32 * 12 = 384 m²
Perimeter = 4 * side
Side = 80/4 = 20 m.
Given one diafgonal, d = 24 m.
A rhombus has four triangles and four of them are right angled triangle.
Length of one side = Diagonal/2 = 12m
Length of other side = 2ndDiagonal/2
Length of hypotenuse = 20m .
Now, According to Pythagoras theorem.
20² - 12² = ( Diagonal /2 )²
400 - 144 = (Diagonal /2 )²
√ 256 = Diagonal / 2
16 = Diagonal /2
Diagonal = 32 m .
We have Diagonals 32 m, 24 m.
Area = 1/2 * 32 * 24 = 32 * 12 = 384 m²
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