Question

find the area of Rhombus whose side 6cm attitude 4 cm if one diagonal is 8 cm find other diagonal

Answer 1

by Pythagoras theorem,

6²=4²+(half of II diagonal)²

36-16=(half of II diagonal)²

√20=half of diagonal=2√5

II diagonal =4√5

area of Rhombus=product of diagonals/2

area of Rhombus=(8*4√5)/2=16√5cm²

I Hope this will help you.

Answer 2

Answer:

Since,a rhombus is also a kind of a parallelogram.

Formula of area of rhombus =Base×Altitude

Putting values, we have

Area of rhombus =6×4=24

Since, Area of rhombus is 24 cm².

Also,formula for area of rhombus =$\frac{1}{2}×d_1d_2$

Given,Length of one diagonal =$d_1$=8

Let length of other diagonal =$d_2$

After substituting the values, we get

$24=\frac{1}{2}×8×d_2$

$24=4×d_2$

$4×d_2=24$

$d_2=\frac{24}{4}$

$d_2=6$

Hence, length of other diagonal is 6 cm.