Question

Find the area of rhombus whose side is 12 cm and altitude is 7cm.if one diagonal is 14 cm long.find the length of othr diagonal

Answer 1

Area of rhombus = base*height

. '. Area of rhombus = 12*7

= 84cm²

also,Area of rhombus

= 1/2*product of its diagonals

1/2*d1*d2 = 84

1/2*14*d2=84

7*d2=84

. '. d2=84/7

. '. d2=12cm

Therefore, the length of other diagonal be 12cm

Hope it helps u

Plz mark as brainliest

Answer 2

The length of other diagonal is $12 cm$.

Step-by-step explanation:

Given:

As shown in the figure given below, we have

Side BC = $12 cm$

Altitude DM = $7 cm$

Diagonal $1$DM = $14 cm$

Diagonal $2$ AC = ?

Now, Area of rhombus = $2\times$Area of triangle BCD

                                      = $2\times\frac{1}{2}\times$                          Base$\times$Altitude

                                      = $2\times\frac{1}{2}\times$ BC $\times$   DM

                                      = $2\times\frac{1}{2}\times12\times7$

                                      = $12\times7$

    Area of rhombus      =$84 cm^2$             $(1)$

We also know that,

Area of rhombus = $\frac{1}{2}$$\times$ Diagonal $1$$\times$ Diagonal$2$

    $84 cm^2$ = $\frac{1}{2}\times14 cm\times$  Diagonal$2$

$\frac{84\times2}{14}$ = Diagonal$2$

$6\times2$ =Diagonal$2$

Hence, Diagonal$2$ = $12 cm$