Question

Find the area of rhombus whose side is 5cm and altitude is 4.8cm and one of its diagonal is 8cms find the length of other diagonal. ​

Answer 1

Answer:

Let the 2nd diagonal of the rhombus be x

Area of the rhombus

=)1/2*5*4. 8=1/2*8*x

=)5*4. 8=8*x

=)x=3

Ans: length of another diagonal is 3cm

Answer 2

Given:-

• The area of rhombus, side is 5cm and altitude is 4.8cm and one of its diagonal is 8cms.

To Find:-

• find the length of other diagonal. ....?

Solutions:-

• Let the length of the other diagonal of the rhombus be x.

A rhombus is a special are of a parallelogram.

The area of a parallelogram is the product of its base and height.

Area of the Rhombus = base × height

= 5cm × 4.8cm

= 24cm²

Area of rhombus = 1/2 (products of its diagonal)

⟹ 24cm² = 1/2 × (8cm + x)

⟹ x = 24 × 2 / 8

⟹ x = 48/8

⟹ x = 6cm

Hence, the length of the other diagonal of the Rhombus is 6cm.

Some Important:-

• A rhombus all side are equal.
• A rhombus opposite angle are equal.
• A rhombus the sum of adjacent angle angle supplementary i.e. (<A + <D = 180°).
• A rhombus, each diagonal of a rhombus divides it into two congruent triangle.
• A rhombus, if one angle is right, then all angle are right.
• Diagonal of a rhombus bisect each other and also perpendicular to each other.

More important:-

1. Area of rhombus = b × h
2. Perimeter of rhombus = 4 × side

where,

• b = base
• h = height
• p = perimeter
• a = area