find the area of Rhombus whose side is 6. 5 cm and altitude is 5 cm. if one of the diagonal is 13 cm long find the length of other diagonol.
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Hey Mate
♣♣♣Answers in attachment ♣♣♣♣
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♣♣♣Answers in attachment ♣♣♣♣
Hope this helps u✌✌✌✌✌
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Answered by
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Heya!
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♦Given that : ABCD is a Rhombus .
↪A B = BC = CD = AD => 6.5 cm
↪Height OA = 5 cm
↪Diagnol D1 = 13 cm
✔Now , we know that area of a parallelogram is Base × Height ! And a Rhombus is also a Parallelogram.
◾Area of Rhombus = Base × Height
= 6.5 × 5
=> 32. 5 cm²
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♦Diagnol D2 = ?
◾Another Formula of area of a Rhombus is ½× d1 × d2
=> 32.5 = 1/2 × 13 × d2
=>> d2 = 5 cm
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===================================================
--------
==========================================================
♦Given that : ABCD is a Rhombus .
↪A B = BC = CD = AD => 6.5 cm
↪Height OA = 5 cm
↪Diagnol D1 = 13 cm
✔Now , we know that area of a parallelogram is Base × Height ! And a Rhombus is also a Parallelogram.
◾Area of Rhombus = Base × Height
= 6.5 × 5
=> 32. 5 cm²
============
♦Diagnol D2 = ?
◾Another Formula of area of a Rhombus is ½× d1 × d2
=> 32.5 = 1/2 × 13 × d2
=>> d2 = 5 cm
=============
===================================================
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