find the area of Rhombus whose side is 6 cm and altitude is 4 cm if one of its diagonals is 8 cm long find the length of the Other diagonal
My question is if area is 4*6 =24=1/2*d*8
Then d=6
But we know diagonal of rhombus bisect each other perpendicularly. So by appying pythogorus theorem(3²+4²=side²) we got side is 5 cm. How in the question side is 6cm. Where is my worng? If you know give me
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Step-by-step explanation:
Ar of rhombus is 1/2(product of diagonals.....
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