Question

Find the area of rhombus whose side is 6cm and whose altitude is 4cm if one its diagonals 8cm long find the length of other diagonal

Answer 1

Let abcd be a rhombus.

Side of rhombus=6 cm

Altitude of rhombus=4 cm.

Area of rhombus abcd=area of triangle ABD+area of triangle BCD

=half into b×h+ half into b×h

=half ×6×4+half×6×4

=12 +12

=24 cm2

Half into d1 ×d2 =24

d1×d2=24×2

8× d2=48

d2 =48 upon 8

d2=6cm

Answer 2

Answer:

Length of the other diagonal = 6cm

Step-by-step explanation:

First we need to find the Area of the Rhombus...

Area of Rhombus = Base x Height

Area of this Rhombus = 6 x 4

                                    = 24cm²

Now that we found the area of the rhombus, we can easily find the Altitude/Height.....

Area of Rhombus = $\frac{1}{2}$ x d₁ x d₂ ( When diagonals are given )

24cm² = $\frac{1}{2}$ x 8 x d₂

24cm² = 4 x d₂

$\frac{24}{4}$ = d₂

6 = d₂

Therefore the length of the other diagonal is = 6cm

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