Math, asked by kuljeetpaul, 1 year ago

find the area of Rhombus whose side is 8 centimetre and whose altitude is 7 cm is one of its diagonals is 16 cm find the length of the Other diagonal

Answers

Answered by Kajal12345
0
area =1/2*8*7
area=.......
Answered by mysticd
1
ABCD is a Rhombus .

AC , BD are two diagonals bisects

perpendicularly at O.

It is given that

AC = d1 = 16 cm

BD = d2 = 2 × OD = 2 × 7 = 14 cm

Area of the Rhombus (A) = ( d1 × d2 )/2

= ( 16 × 14 )/2

= 16 × 7

= 112 cm²

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