find the area of Rhombus whose side is 8 centimetre and whose altitude is 7 cm is one of its diagonals is 16 cm find the length of the Other diagonal
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area =1/2*8*7
area=.......
area=.......
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ABCD is a Rhombus .
AC , BD are two diagonals bisects
perpendicularly at O.
It is given that
AC = d1 = 16 cm
BD = d2 = 2 × OD = 2 × 7 = 14 cm
Area of the Rhombus (A) = ( d1 × d2 )/2
= ( 16 × 14 )/2
= 16 × 7
= 112 cm²
•••••
AC , BD are two diagonals bisects
perpendicularly at O.
It is given that
AC = d1 = 16 cm
BD = d2 = 2 × OD = 2 × 7 = 14 cm
Area of the Rhombus (A) = ( d1 × d2 )/2
= ( 16 × 14 )/2
= 16 × 7
= 112 cm²
•••••
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