find the area of rhombus whose side is 8cm and altitude is 5cm if one of its diagonal is 10cm long find the length of other diagonal
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Answer:-
Side (let it be base bcz each side is equal to another)=8 cm.
Height=7cm
Area of rhombus=
base \times heightbase×height
= 8 \times 7=8×7
= 56 \: cm {}^{2}=56cm
2
We know that
Area of rhombus
= \frac{1}{2} \times diagonal \: 1 \times diagonal \: 2=
2
1
×diagonal1×diagonal2
Equating the area.
56 = \frac{1}{2} \times 16 \times diagonal \: 256=
2
1
×16×diagonal2
56 = 8 \times diagonal \: 256=8×diagonal2
\frac{56}{8} = diagonal \: 2
8
56
=diagonal2
7 \: cm = diagonal \: 27cm=diagonal2
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