Find the area of rhombus whose verties are (1, 1), (5, 3), (7, 7), (3, 5).
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find the area of a rhombus if its vertices are (3,0),(4,5),(−1,4)and(−2,−1) taken in order.
December 20, 2019avatar
Bhagya Jyothi
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Let the points are A(3,0), B(4,5), C(-1,4) and D(-2,-1)
BD=
(−2−4)
2
+(−1−5)
2
=
(−6)
2
+(−6)
2
=
36+36
=
72
=6
2
units
AC=
(−1−3)
2
+(4−0)
2
=
(−4)
2
+(4)
2
=
16+16
=
32
Now, area of rhombus ABCD
=
2
1
× (Product of diagonals)
⇒ Area of rhombus =
2
1
×(AC×BD)
=[
2
1
×4
2
×6
2
] sq. units
=(2
2
×6
2
) sq. units = 24 sq. units.
solution
Answered by
1
Answer:
2,2
4,4
6,0
48,746
I hope its correct
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