Math, asked by goondlamukeshgoud26, 9 months ago

Find the area of rhombus whose verties are (1, 1), (5, 3), (7, 7), (3, 5).​

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Answered by mdazamfaizy
2

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find the area of a rhombus if its vertices are (3,0),(4,5),(−1,4)and(−2,−1) taken in order.

December 20, 2019avatar

Bhagya Jyothi

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ANSWER

REF.Image

Let the points are A(3,0), B(4,5), C(-1,4) and D(-2,-1)

BD=

(−2−4)

2

+(−1−5)

2

=

(−6)

2

+(−6)

2

=

36+36

=

72

=6

2

units

AC=

(−1−3)

2

+(4−0)

2

=

(−4)

2

+(4)

2

=

16+16

=

32

Now, area of rhombus ABCD

=

2

1

× (Product of diagonals)

⇒ Area of rhombus =

2

1

×(AC×BD)

=[

2

1

×4

2

×6

2

] sq. units

=(2

2

×6

2

) sq. units = 24 sq. units.

solution

Answered by gaurav2456
1

Answer:

2,2

4,4

6,0

48,746

I hope its correct

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