Question

Find the area of right angle triangle with base as 16cm and height as 4cm.​

Answer 1

Given :

★ Base of Right angled triangle = 16 cm

★ Height of Right angled triangle = 4 cm

To Find :

★ Area of Right angled triangle .

Formula Used :

$\sf{(\:\:Area\:of\:Triangle=\dfrac{1}{2}\times{b}\times{h}\:\:)}$

Solution :

Base = 16 cm

Height = 4 cm

Now :

1/2 × b × h

1/2 × 16 × 4

16 × 2

32

Hence , The Area of the Right angled triangle is 32 cm² .

Answer 2

Given :

$\bullet \: \: \textsf{The area of right angle triangle with base as 16cm and height as 4cm.}$

To Find :

$\bullet \: \: \textsf{The area of right angle triangle = ?}$

Answer :

$\bullet\:\:\textsf{The Area of traingle is \textbf{32 cm ^{\text 2} }}.$

Explaination :

• Base = 16 cm
• Height = 4 cm

As we know that, area right angle traingle is calculated by :

$\bigstar\: \: \textsf {Area of \Delta = \dfrac{\text 1}{\text 2} \times Base \times Height }$

Now, Substituting the value of base and height in the above formula :

$: \implies\textsf {Area of \Delta = \dfrac{\text 1}{\text 2} \times 16 \times 4}$

$: \implies\textsf {Area of \Delta = 8 \times 4}$

$:\implies \underline{ \boxed{\textsf { \textbf{Area of \Delta = 32 cm ^{ \text2} }} }}$

$\therefore\:\underline{\textsf{The Area of traingle is \textbf{32 cm ^{\text 2} }}}.$

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More to know:

• Area of right angled triangle = 1/2 × b × h

• Area of triangle using Heron's formula = √s(s - a)(s - b)(s - c)