Find the area of right angled triangle ABC, if AB=5cm, AC=13cm and √B=90.
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Answer:
In rt ️ ABC
By pythagoras theorem
AC²=AB²+BC²
13²=5²+BC²
169=25+BC²
BC²=169-25
BC²=144
BC=√144
BC=12cm
Ar of ️= ½×AB×BC
=½×5×12
30cm
Answered by
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GIVEN:
A right triangle ABC with ∠B = 90⁰
AB = 5cm
AC = 13cm
SOLUTION:
In right triangle ABC,
AB² + BC² = AC² (pythagoras theorem)
==> BC² = AC² - AB²
==> BC² = (13)² - (5)²
==> BC² = 169 - 25
==> BC = √144
==> BC = 12
∴ The base BC is 12 cm
Area of a right triangle = 1/2×base×height
= 1/2 × 5 × 12
= 6 × 5
= 30
∴Required area of the triangle is 30 cm²
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