Question

Find the area of
right-angled triangle
∆ABC where ac=12cm
angle abc=angle acb

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Answer 1

area of right angle traingle=ab/2

=12×12/2=144÷2=72

Answer 2

Answer:

As angle abc=angle acb

therefore,it is an isosceles right angled ∆

it implies,ab=ac=12cm

Hence area of the ∆ ABC = 1/2 × ab× ac

=1/2×12×12=144/2=72cm2