Question

Find the area of right angled triangle if it prependicular =60 cm and hypotenuse =61 in maths of 7th standard

Answer 1

$\huge \bf \red{ \mid{ \overline{ \underline{ANSWER}}} \mid}$


$\bf {QUESTION}$
Find the area of right angled triangle if it prependicular =60 cm and hypotenuse =61 in maths of 7th standard

$\bf{step \: by \: step \: explanation}$

$\bf{Given}$

Prependicular (p) = 60cm

Hypotenuse (h) = 61 cm

Base (b) =?

$\bf{ \degree . \degree\: it \: is \: right \: angled \: triangle}$

$\bf{. \degree. \: we \: use \: pythagores \: theorem}$

$\bf{ {(b)}^{2} = {(h)}^{2} - {(p)}}^{2}$


$\bf{b = \sqrt{ {61}^{2} - {60}^{2} }}$


$\bf{b = \sqrt{3721 - 3600}}$


$\bf{b = \sqrt{121}}$

$\bf {\implies \: b = 11cm}$

Now area

$\bf{ \frac{1}{2} \times b \times h}$

$\bf{ \frac{1}{2} \times 11 \times 60}$

$\bf{ \frac{1}{ \cancel{2}} \times 11 \times \cancel{60} \: 30}$

$\bf{ \implies \: 11 \times 30}$

$\huge \bf{ \implies 330 {cm}}^{2}$



$\huge \bf \pink \mid{ \orange{thanks}} \pink {{\mid}}$

Answer 2

Answer:

Area of right Angled Triangle = 330 cm².

Step-by-step explanation:

Pythagoras theorem : In a right Angled Triangle , the sum of Square of two side of Triangle is Equal to the Square of other side.

Now, In this Question, It is given that prependicular and hypotenuse are 60 and 61 respectively.

Using Pytogoras theorem!

H² = P² + B² , Where H represent Hypotenuse , P represent Perpendicular and B represent Base of right Angled Triangle.

Substituting Given Value!

H² = P² + B²

( 61 ) ² = (60)² + B²

B² = 121

•°• B = √121

Base = 11 cm

Now, According to the Question!

{ We have to find the are of right Triangle }

•°• Area of Right Triangle = 1/2 × Base × Height

☛ Area of Right Triangle = 1/2 × 11 × 60

= 11 × 30 cm²

= 330 cm²

Therefore,   Area of right Angled Triangle = 330 cm².