Find the area of right angled triangle if its perpendicular=60cm,hypotenuse=61cm
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Pythagoras to be used that is :
Perpendicular ^2 × base ^2 = hypotenuse^2
As given in question :
Perpendicular = 60
Hypotenuse = 61
Let base be = y
Perpendicular ^2 × base ^
2 = hypotenuse^2
60^2. ×. Y ^2 (say). = 61^2
3600 × y^2 = 3721
Y^2 = 3721-3600
y^2 = 121
Y = √121
Y= 11
Congratulations we found base that is 11cm .
Now ,
As we all know...
Area =ab/2
[Where , a is perpendicular = 61
And
b = base that is 11 cm ]
Area = 60×11/2 = 330
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