Question

find the area of right angled triangle if the radius of its circumcircle is 8 cm and altitude drawn to the hypotenuse is 6cm

Answer 1

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Answer 2

$\\ \boxed{ \rm \: let \: \triangle \: abc \: be \: right \: angled \: at \: B}$

$\textsf{Then hypotenus \: AC = diameter \: of \: its \: circumcircle}$

$\textsf{ = (6 × 8) = 48cm}$

$\textsf{Let BL⏊AC .Then,BL=2cm}$

$\textsf{Area of triangle ABC}= \rm \huge {\frac{1}{2}} \small ×AC×BL$

$\rm = \large \big( \frac{1}{2} \times 8\times 6\big)cm {}^{2} = 24cm {}^{2}$