Question

Find the area of right angled triangle whose sides forming an right angle are 13cm and 9 cm​

Answer 1

Three ways of doing it :

According to pythogaras theorem,

5² + 12² = 13²

=> 5 & 12 or 12 & 5 is the base and altitude of the triangle respectively.

=> Area = ½ x base x altitude

= ½ x 5 x 12 = 30 cm²

Use Heron’s Formula

A = √{s(s - a)(s - b)(s - c)} where s = (a+b+c)/2

=> s = (5+12+13)/2 = 15

Area = √(15x 10 x 3 x 2) = √900 = 30 cm²

Use sin formula

Area = ½ x a x b x sin (theta)

=> ½ x 5 x 12 x Sin 90°

= 30 x Sin 90° = 30 x 1 = 30 cm²

The formula for the area of a triangle is bh/2

(half base×height)

(12*5)2 = 30cm²

Answer 2

Answer:

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