find the area of right isoseles triangle of hypotenense 20 cm
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Hypotenuse=20 cm
Hypotenuse=20 cmAccording to Pythagoras theorem,
Hypotenuse=20 cmAccording to Pythagoras theorem,Hypotenuse ²=side²+side²
Hypotenuse=20 cmAccording to Pythagoras theorem,Hypotenuse ²=side²+side²Let hypotenuse=a
Hypotenuse=20 cmAccording to Pythagoras theorem,Hypotenuse ²=side²+side²Let hypotenuse=aBase=b
Hypotenuse=20 cmAccording to Pythagoras theorem,Hypotenuse ²=side²+side²Let hypotenuse=aBase=bHeight=c
Hypotenuse=20 cmAccording to Pythagoras theorem,Hypotenuse ²=side²+side²Let hypotenuse=aBase=bHeight=cIn an isosceles right angled triangle,
Hypotenuse=20 cmAccording to Pythagoras theorem,Hypotenuse ²=side²+side²Let hypotenuse=aBase=bHeight=cIn an isosceles right angled triangle,The other two sides are equal.
Hypotenuse=20 cmAccording to Pythagoras theorem,Hypotenuse ²=side²+side²Let hypotenuse=aBase=bHeight=cIn an isosceles right angled triangle,The other two sides are equal.So,base=height=b
Hypotenuse=20 cmAccording to Pythagoras theorem,Hypotenuse ²=side²+side²Let hypotenuse=aBase=bHeight=cIn an isosceles right angled triangle,The other two sides are equal.So,base=height=bApply Pythagoras theorem,
Hypotenuse=20 cmAccording to Pythagoras theorem,Hypotenuse ²=side²+side²Let hypotenuse=aBase=bHeight=cIn an isosceles right angled triangle,The other two sides are equal.So,base=height=bApply Pythagoras theorem,a²=b²+b²
Hypotenuse=20 cmAccording to Pythagoras theorem,Hypotenuse ²=side²+side²Let hypotenuse=aBase=bHeight=cIn an isosceles right angled triangle,The other two sides are equal.So,base=height=bApply Pythagoras theorem,a²=b²+b²a²=2b²
Hypotenuse=20 cmAccording to Pythagoras theorem,Hypotenuse ²=side²+side²Let hypotenuse=aBase=bHeight=cIn an isosceles right angled triangle,The other two sides are equal.So,base=height=bApply Pythagoras theorem,a²=b²+b²a²=2b²b=√(a²/2)
Hypotenuse=20 cmAccording to Pythagoras theorem,Hypotenuse ²=side²+side²Let hypotenuse=aBase=bHeight=cIn an isosceles right angled triangle,The other two sides are equal.So,base=height=bApply Pythagoras theorem,a²=b²+b²a²=2b²b=√(a²/2)b=√(20²/2)
Hypotenuse=20 cmAccording to Pythagoras theorem,Hypotenuse ²=side²+side²Let hypotenuse=aBase=bHeight=cIn an isosceles right angled triangle,The other two sides are equal.So,base=height=bApply Pythagoras theorem,a²=b²+b²a²=2b²b=√(a²/2)b=√(20²/2)b=20/√2
Hypotenuse=20 cmAccording to Pythagoras theorem,Hypotenuse ²=side²+side²Let hypotenuse=aBase=bHeight=cIn an isosceles right angled triangle,The other two sides are equal.So,base=height=bApply Pythagoras theorem,a²=b²+b²a²=2b²b=√(a²/2)b=√(20²/2)b=20/√2Area of isosceles right angled triangle=1/2×b×h
Hypotenuse=20 cmAccording to Pythagoras theorem,Hypotenuse ²=side²+side²Let hypotenuse=aBase=bHeight=cIn an isosceles right angled triangle,The other two sides are equal.So,base=height=bApply Pythagoras theorem,a²=b²+b²a²=2b²b=√(a²/2)b=√(20²/2)b=20/√2Area of isosceles right angled triangle=1/2×b×h=1/2×20/√2×20/√2
Hypotenuse=20 cmAccording to Pythagoras theorem,Hypotenuse ²=side²+side²Let hypotenuse=aBase=bHeight=cIn an isosceles right angled triangle,The other two sides are equal.So,base=height=bApply Pythagoras theorem,a²=b²+b²a²=2b²b=√(a²/2)b=√(20²/2)b=20/√2Area of isosceles right angled triangle=1/2×b×h=1/2×20/√2×20/√2=1/2×400/2
Hypotenuse=20 cmAccording to Pythagoras theorem,Hypotenuse ²=side²+side²Let hypotenuse=aBase=bHeight=cIn an isosceles right angled triangle,The other two sides are equal.So,base=height=bApply Pythagoras theorem,a²=b²+b²a²=2b²b=√(a²/2)b=√(20²/2)b=20/√2Area of isosceles right angled triangle=1/2×b×h=1/2×20/√2×20/√2=1/2×400/2=400/4
Hypotenuse=20 cmAccording to Pythagoras theorem,Hypotenuse ²=side²+side²Let hypotenuse=aBase=bHeight=cIn an isosceles right angled triangle,The other two sides are equal.So,base=height=bApply Pythagoras theorem,a²=b²+b²a²=2b²b=√(a²/2)b=√(20²/2)b=20/√2Area of isosceles right angled triangle=1/2×b×h=1/2×20/√2×20/√2=1/2×400/2=400/4=100 cm²