Question

Find the area of right triangle ABC with base be = 7cm and hypotenuse = 25cm

Answer 1

Here's the answer

Refer the attachment for the figure

In ∆ABC,

Angle ABC = 90°

BC = base = 7 cm

AC = hypotenuse = 25 cm

AB = height = ?


So,

By Pythagoras theorem,

AB^2 + BC^2 = AC^2

AB^2 + 7^2 = 25^2

AB^2 + 49 = 625

AB^2 = 625 - 49

AB^2 = 576

AB = √576

AB = 24 cm

Thus,

We got AB as height as 24 cm

So,

We know that,

Area of triangle = 1/2 × base × height

= 1/2 × 7 × 24

= 1 × 7 × 12

= 84 cm^2


So,

Area of triangle = 84 sq.cm

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