Question

find the area of right triangle whose base is 1.2 M and hypotenuse 3.7 metre

Answer 1

h^2 = 1.2^2 +l^2
l =
$\sqrt{3.7 { }^{2} - 1.2 {}^{2} }$
= 3.53

area = 1.2*3.53/2 = 2.118 m^2

Answer 2

Answer:

2.1 sq.m.

Step-by-step explanation:

Base = 1.2 m

Hypotenuse = 3.7 m

Using Pythagorean theorem;

$Hypotenuse^2=Perpendicular^2+Base^2$

$3.7^2=Perpendicular^2+1.2^2$

$3.7^2-1.2^2=Perpendicular^2$

$\sqrt{3.7^2-1.2^2}=Perpendicular$

$3.5=Perpendicular$

Area of triangle = $\frac{1}{2} \times Base \times Height$

                           = $\frac{1}{2} \times 1.2 \times 3.5$

                           = $2.1 m^2$

Hence the area of triangle is 2.1 sq.m.