Question

find the area of right triangle whose hypotenuse is 13 cm and one side is 5cm.​

Answer 1

Answer

Area of the rectangle = 30 cm²

Given

One side of right angled triangle is 5 cm

Hypotenuse of right angled triangle is 13 cm

To Find

Area of right angled triangle

Have a look at

We have one side and hypotenuse of right angles triangle , so to find other side we need to apply Pythagoras theorem .

Area of triangle ,

$\rm{\pink{A=\dfrac{1}{2}\times b\times h\ \; \bigstar}}$

Solution

Apply pythagoras theorem for finding remaining side of right angled triangle ,

Let that be , " x "

$\to\ \rm x^2+5^2=13^2\\\\\to\ \rm x^2+25=169\\\\\to\ \rm x^2=169-25\\\\\to\ \rm x^2=144\\\\\to\ \rm{\green{x=12\ cm\ \; \bigstar}}$

So , base of the triangle = 12 or 5

height of the triangle = 5 or 12

Apply formula ,

$\to\ \rm A=\dfrac{1}{2}\times 5\times 12\\\\\to\ \rm A=5\times 6\\\\\to\ \rm{\blue{A=30\ cm^2\ \; \bigstar}}$

So , Area of the rectangle = 30 cm²

Answer 2

ANSWER:-

➣

• Given:-

One side of rght. angled triangle($\triangle$)=$\bf{5 \: cm}$

Hypotenuse[H] of right angled triangle= $\bf{13 \: cm}$

• To Find:-

Area of right angled triangle

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• FORMULA:-

$\boxed{\bf{A=\dfrac{1}{2}\times b\times h}}$

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Applying Pythagoras THEOREM:-

$\boxed{\bf{(Perpendicular)^2 + (Base)^2 = (Hypotenuse)^2}}$

Assume that side be, $\bf{" x "}$

$\longrightarrow{x^2+5^2=13^2}$

$\longrightarrow{x^2+25=169}$

$\longrightarrow{x^2=169-25}$

$\longrightarrow{x^2=144}$

$\implies \bf{x=12 \: cm}$

Applying formula of Area:-

$A=\dfrac{1}{2}\times 5\times 12$

$A=5\times 6$

$\large{\bf{A=30\ cm^2}}$

•Therefore,

$\large \bf {Area \: of \: the \: rectangle = 30 cm^2}$

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