Question

find the area of right triangle whose hypotenuse is 13 cm and one side is 5cm

Answer 1

prependicular)^2 = (hypotenous)^2 - (base)^2
(p)^2 = (13)^2 - (5)^2
p^2 = 169-25
p^2 = 144
p = 12cm

area of right angle traingle = 1/2 × base × height
= 1/2 × 5 × 12
= 30cm^2

Answer 2

$\huge{Answer \ :-}$

By Pythagoras Theorem :-

${(hyp)}^{2} = {(h)}^{2} + {(b)}^{2}$

${(13)}^{2} = {(5)}^{2} + {(b)}^{2}$

$169 = 25 + {(b)}^{2}$

$169 - 25 = {(b)}^{2}$

$144 = {(b)}^{2}$

$\sqrt{144} = {(b)}^{2}$

$12 = base$

Area of Triangle = $\dfrac{1}{2}$ × b × h

= $\dfrac{1}{2}$ × 5 × 12

$= {30 \: cm}^{2}$

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