Question

find the area of right triangle whose hypotenuse is 13cm and one side is 5cm​

Answer 1

Answer:

$are \: of \: trianle \: = {13}^{2} + {5}^{2} \\ = 169 + 25 \\ = 194 \\ taking \: square \: root \\ are \: of \: right \: triahgle \: = \sqrt{194}$

Answer 2

Answer:

Area=$30cm^{2}$

Step-by-step explanation:

Given:

Hypotenuse = 13cm

Base = xcm(It is not given)

Height = 5cm

Using RHS:

$AB^{2}=AC^{2}+BC^{2}$

$13^{2}=5^{2}+x^{2}$

$169=25+x^{2}$

$169-25=x^{2}$

$144=x^{2}$

$\sqrt{144}=x$

∴$x=12$

To find Area:

Area=$\frac{1}{2}$×b×h

Area=$\frac{1}{2}$×12×5

Area=$30cm^{2}$