Question

find the area of right triangle whose hypotenuse is 13cm and one side is 5cm​

Answer 1

using pytho..... therom
let the unknown side be X

13^2 = 5^2 + x^2
169 = 25 +x^2
169-25 = X^2

X=12

by using herons formula

√(15-13*15-12*15-5)
√ ( 2*3*10)
√60
7.745966692414833770358530799 is the area


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Answer 2

Answer:

Area=$30cm^{2}$

Step-by-step explanation:

Given:

Hypotenuse = 13cm

Base = xcm(It is not given)

Height = 5cm

Using RHS:

$AB^{2}=AC^{2}+BC^{2}$

$13^{2}=5^{2}+x^{2}$

$169=25+x^{2}$

$169-25=x^{2}$

$144=x^{2}$

$\sqrt{144}=x$

∴$x=12$

To find Area:

Area=$\frac{1}{2}$×b×h

Area=$\frac{1}{2}$×12×5

Area=$30cm^{2}$