Question

find the area of right triangle with hyp 20 cm and one angle is 48 degree


(spam allow)​

Answer 1

$\mathfrak\red{Answer - }$

⚡Let △ABC is the right angle triangle, right angled at B & ∠C=48°

Now,

$\bf{⇒sin48°= \frac{AB}{AC} = \frac{AB}{20} }$

⇒AC=20 sin48°=20×0.7431

⇒AC=14.862cm

$\bf\green{Again,}$

$\bf{⇒cos48°= \frac{BC}{AC} = \frac{BC}{20} }$

⇒BC=20×cos48°=20×0.6691

⇒BC=13.382

$\bf\red{Now, \: area \: △ABC= \frac{1}{2} × \: base \: × \: height}</p><p>$

$= \: \bf{ \frac{1}{2} ×13.382×14.862}$

$\bf\purple{= {99.42cm}^{2} }$

Hence the answer is 99.42cm^2⛄

Answer 2

Step-by-step explanation:

Let △ABC is the right angle triangle, right angled at B & ∠C=48°

Now,

⇒sin48°=

AC

AB

=

20

AB

⇒AC=20sin48°=20×0.7431

⇒AC=14.862cm

Again,

⇒cos48°=

AC

BC

=

20

BC

⇒BC=20×cos48°=20×0.6691

⇒BC=13.382

Now, area △ABC=

2

1

×base×height

=

2

1

×13.382×14.862

=99.42cm

2

Hence the answer is 99.42cm

2

.

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