Question

Find the area of sector of a circle with radius 6 cm If angle of sector is 60°

Answer 1

area of sector =Φ/360°*πr²
WhereΦ=angle of sector
area =6*6*22/6*7
=792/42=18.85
area of sector =18.85cm²

Answer 2

Answer:

18.85 $cm^2$ is the required area of the sector .

Step-by-step explanation:

Explanation:

Given , radius of circle = 6cm and the angle of sector = 60 ° .

Area of sector = $\frac{\theta }{360 }$ ×$\pi r^{2}$

Now  , put the value of radius and the angle in the above formula we get

Area of sector = $\frac{60}{360}$ × $\pi (6)^2$

Area of sector = $\frac{1}{6}$ × $\pi (6)^{2}$ = 6$\pi$ = 6 ×$\frac{22}{7}$ =$\frac{132} {7} cm^2$ = 18 .85 $cm^2$

Final answer:

Hence , the area of the  sector = 18.85 $cm^2$ .

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