Question

find the area of sector of a circle with radius 6 cm if angle of the sector is 60*.

$\pi = 22 \div 7$
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Answer 1

Answer:

area of sector = thee ta/360×pi×r^2

=60/360×22/7×6×6

=22/7×6

=18.85 cm2

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Answer 2

Step-by-step explanation:

$\mathfrak{ \huge{ \green{ \underline{given}}}} \\ \mathfrak{ \large{ \red{radius \: = \: 6 \: cm}}} \\ \mathfrak{ \large{ \red{angle \: of \: sector \: (θ) = {60}^{o}}}} \\ \mathfrak{ \huge{ \green{ \underline{to \: find}}}} \\ \mathfrak{ \large{ \red{area \: of \: sector \: = \: ?}}} \\ \mathfrak{ \huge{ \green{ \underline{formula \: to \: be \: used}}}} \\ \mathfrak{ \large{ \red{area \: of \: sector \: = \: \frac{θ}{360} \: \times \: \pi {r}^{2} }}} \\ \mathfrak{ \huge{ \green{ \underline{solution}}}} \\ \mathfrak{ \large{ \blue{area \: of \: sector \: = \frac{θ}{360} \times \pi {r}^{2}}}} \\ \mathfrak{ \large{ \blue{area \: of \: sector \: = \: \frac{60}{360} \times \frac{22}{7} \times 6 \times 6 }}} \\ \mathfrak{ \large{ \blue{area \: of \: sector \: = \: \frac{1}{6} \times \frac{22}{7} \times 6 \times 6 }}} \\ \mathfrak{ \large{ \blue{area \: of \: sector \: = \: \frac{22}{7} \times 6}}} \\ \mathfrak{ \large{ \orange{ \underline{area \: of \: sector \: = \: \frac{132}{7} {cm}^{2} }}}}$